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Catch URLError from firewall and give practical advice

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This commit is contained in:
Steve Barnes
2017-08-08 11:45:59 +01:00
parent 404ac70b1b
commit 2eea0a5634
1 changed files with 11 additions and 3 deletions
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14
wx/tools/wxget.py
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@@ -32,12 +32,12 @@ import os
import wx import wx
if sys.version_info >= (3,): if sys.version_info >= (3,):
from urllib.error import HTTPError from urllib.error import (HTTPError, URLError)
import urllib.request as urllib2 import urllib.request as urllib2
import urllib.parse as urlparse import urllib.parse as urlparse
else: else:
import urllib2 import urllib2
from urllib2 import HTTPError from urllib2 import (HTTPError, URLError)
import urlparse import urlparse
def get_docs_demo_url(demo=False): def get_docs_demo_url(demo=False):
@@ -100,7 +100,15 @@ def download_file(url, dest=None, force=False):
try: try:
url_res = urllib2.urlopen(url) url_res = urllib2.urlopen(url)
keep_going = True keep_going = True
except HTTPError as err: except (HTTPError, URLError) as err:
msg = '\n'.join([
"\n\nERROR in Web Access! - you may be behind a firewall",
"You may be able to bybass this by using a browser to download:",
"\n\t%s\n\nand copying to:\n\n\t%s" % (url, filename),
])
print(msg, '\n')
wx.MessageBox(msg, caption='WDOWNLOAD ERROR!',
style=wx.OK|wx.CENTRE|wx.ICON_ERROR)
return "Error: %s" % err return "Error: %s" % err
with open(filename, 'wb') as outfile: with open(filename, 'wb') as outfile: