py: Make list.sort keep stack usage within O(log(N)) bound.

Also fix list.sort so it works with user-defined types, and parse the
keyword arguments properly.

Addresses issue #338.
This commit is contained in:
Damien George
2015-02-02 15:14:22 +00:00
parent ae3150cb5c
commit 744e767458
2 changed files with 54 additions and 22 deletions

View File

@@ -26,3 +26,24 @@ l.sort(reverse=False)
print(l)
print(l == sorted(l, reverse=False))
# test large lists (should not stack overflow)
l = list(range(2000))
l.sort()
print(l[0], l[-1])
l.sort(reverse=True)
print(l[0], l[-1])
# test user-defined ordering
class A:
def __init__(self, x):
self.x = x
def __lt__(self, other):
return self.x > other.x
def __repr__(self):
return str(self.x)
l = [A(5), A(2), A(1), A(3), A(4)]
print(l)
l.sort()
print(l)
l.sort(reverse=True)
print(l)