From 5f0de766b28948640f0f17d07163f4dc760772d7 Mon Sep 17 00:00:00 2001
From: jiw <35237843+ghjwp7@users.noreply.github.com>
Date: Sun, 12 Jan 2025 22:12:59 -0700
Subject: [PATCH] =?UTF-8?q?Another=20#=C2=A0this=20will=20print=201,=202,?=
 =?UTF-8?q?=203,=204=20->=20#=C2=A0this=20will=20print=201,=202,=203=20+?=
 =?UTF-8?q?=20"will=20extract=20modify"=20->=20"will=20modify"?=
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---
 Improving-performance-with-Viper-code.md | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/Improving-performance-with-Viper-code.md b/Improving-performance-with-Viper-code.md
index e76a3dd..0090c4d 100644
--- a/Improving-performance-with-Viper-code.md
+++ b/Improving-performance-with-Viper-code.md
@@ -343,7 +343,7 @@ myfunction( array.array("l", (1,2,3,4)))
 def myfunction( )->int:
     int32_array = array.array("l", (1,2,3,4))
     x = ptr32( int32_array )
-    print(x[0], x[1], x[2] ) # this will print 1, 2, 3, 4
+    print(x[0], x[1], x[2] ) # this will print 1, 2, 3
     ba = bytearray(10)
     y = ptr8(ba)
     y[0] = 1 # This will change ba[0]
@@ -398,7 +398,7 @@ If x is a ptr8, x[n] will always be between 0 and 255.
 
 * If x is a ptr16, `x[n] = v` will extract the least two significant bytes of the Viper integer `v`and modify the two byte at x[n]
 
-* If x is a ptr32, `x[n] = v` will extract modify the four bytes at `x[n]` with the Viper integer v.
+* If x is a ptr32, `x[n] = v` will modify the four bytes at `x[n]` with the Viper integer v.
 
 In all cases you will need to convert to a Viper `int` first.